x^(1/2)=x-20

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Solution for x^(1/2)=x-20 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

x^(1/2) = x-20 // - x-20

x^(1/2)-x+20 = 0

t_1 = x^(1/2)

1*t_1^1-1*t_1^2+20 = 0

t_1-t_1^2+20 = 0

DELTA = 1^2-(-1*4*20)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)-1)/(-1*2) or t_1 = (-81^(1/2)-1)/(-1*2)

t_1 = -4 or t_1 = 5

t_1 = -4

x^(1/2)+4 = 0

1*x^(1/2) = -4 // : 1

x^(1/2) = -4

( -4 < 0 i 1/2 in (0:1) ) => x należy do O

t_1 = 5

x^(1/2)-5 = 0

1*x^(1/2) = 5 // : 1

x^(1/2) = 5

x^(1/2) = 5 // ^ 2

x = 25

x = 25

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